Optimal. Leaf size=222 \[ -117 c^2 d^{15/2} \left (b^2-4 a c\right )^{5/4} \tan ^{-1}\left (\frac {\sqrt {d (b+2 c x)}}{\sqrt {d} \sqrt [4]{b^2-4 a c}}\right )-117 c^2 d^{15/2} \left (b^2-4 a c\right )^{5/4} \tanh ^{-1}\left (\frac {\sqrt {d (b+2 c x)}}{\sqrt {d} \sqrt [4]{b^2-4 a c}}\right )+234 c^2 d^7 \left (b^2-4 a c\right ) \sqrt {b d+2 c d x}-\frac {13 c d^3 (b d+2 c d x)^{9/2}}{2 \left (a+b x+c x^2\right )}-\frac {d (b d+2 c d x)^{13/2}}{2 \left (a+b x+c x^2\right )^2}+\frac {234}{5} c^2 d^5 (b d+2 c d x)^{5/2} \]
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Rubi [A] time = 0.18, antiderivative size = 222, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 7, integrand size = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.269, Rules used = {686, 692, 694, 329, 212, 206, 203} \begin {gather*} 234 c^2 d^7 \left (b^2-4 a c\right ) \sqrt {b d+2 c d x}-117 c^2 d^{15/2} \left (b^2-4 a c\right )^{5/4} \tan ^{-1}\left (\frac {\sqrt {d (b+2 c x)}}{\sqrt {d} \sqrt [4]{b^2-4 a c}}\right )-117 c^2 d^{15/2} \left (b^2-4 a c\right )^{5/4} \tanh ^{-1}\left (\frac {\sqrt {d (b+2 c x)}}{\sqrt {d} \sqrt [4]{b^2-4 a c}}\right )-\frac {13 c d^3 (b d+2 c d x)^{9/2}}{2 \left (a+b x+c x^2\right )}-\frac {d (b d+2 c d x)^{13/2}}{2 \left (a+b x+c x^2\right )^2}+\frac {234}{5} c^2 d^5 (b d+2 c d x)^{5/2} \end {gather*}
Antiderivative was successfully verified.
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Rule 203
Rule 206
Rule 212
Rule 329
Rule 686
Rule 692
Rule 694
Rubi steps
\begin {align*} \int \frac {(b d+2 c d x)^{15/2}}{\left (a+b x+c x^2\right )^3} \, dx &=-\frac {d (b d+2 c d x)^{13/2}}{2 \left (a+b x+c x^2\right )^2}+\frac {1}{2} \left (13 c d^2\right ) \int \frac {(b d+2 c d x)^{11/2}}{\left (a+b x+c x^2\right )^2} \, dx\\ &=-\frac {d (b d+2 c d x)^{13/2}}{2 \left (a+b x+c x^2\right )^2}-\frac {13 c d^3 (b d+2 c d x)^{9/2}}{2 \left (a+b x+c x^2\right )}+\frac {1}{2} \left (117 c^2 d^4\right ) \int \frac {(b d+2 c d x)^{7/2}}{a+b x+c x^2} \, dx\\ &=\frac {234}{5} c^2 d^5 (b d+2 c d x)^{5/2}-\frac {d (b d+2 c d x)^{13/2}}{2 \left (a+b x+c x^2\right )^2}-\frac {13 c d^3 (b d+2 c d x)^{9/2}}{2 \left (a+b x+c x^2\right )}+\frac {1}{2} \left (117 c^2 \left (b^2-4 a c\right ) d^6\right ) \int \frac {(b d+2 c d x)^{3/2}}{a+b x+c x^2} \, dx\\ &=234 c^2 \left (b^2-4 a c\right ) d^7 \sqrt {b d+2 c d x}+\frac {234}{5} c^2 d^5 (b d+2 c d x)^{5/2}-\frac {d (b d+2 c d x)^{13/2}}{2 \left (a+b x+c x^2\right )^2}-\frac {13 c d^3 (b d+2 c d x)^{9/2}}{2 \left (a+b x+c x^2\right )}+\frac {1}{2} \left (117 c^2 \left (b^2-4 a c\right )^2 d^8\right ) \int \frac {1}{\sqrt {b d+2 c d x} \left (a+b x+c x^2\right )} \, dx\\ &=234 c^2 \left (b^2-4 a c\right ) d^7 \sqrt {b d+2 c d x}+\frac {234}{5} c^2 d^5 (b d+2 c d x)^{5/2}-\frac {d (b d+2 c d x)^{13/2}}{2 \left (a+b x+c x^2\right )^2}-\frac {13 c d^3 (b d+2 c d x)^{9/2}}{2 \left (a+b x+c x^2\right )}+\frac {1}{4} \left (117 c \left (b^2-4 a c\right )^2 d^7\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {x} \left (a-\frac {b^2}{4 c}+\frac {x^2}{4 c d^2}\right )} \, dx,x,b d+2 c d x\right )\\ &=234 c^2 \left (b^2-4 a c\right ) d^7 \sqrt {b d+2 c d x}+\frac {234}{5} c^2 d^5 (b d+2 c d x)^{5/2}-\frac {d (b d+2 c d x)^{13/2}}{2 \left (a+b x+c x^2\right )^2}-\frac {13 c d^3 (b d+2 c d x)^{9/2}}{2 \left (a+b x+c x^2\right )}+\frac {1}{2} \left (117 c \left (b^2-4 a c\right )^2 d^7\right ) \operatorname {Subst}\left (\int \frac {1}{a-\frac {b^2}{4 c}+\frac {x^4}{4 c d^2}} \, dx,x,\sqrt {d (b+2 c x)}\right )\\ &=234 c^2 \left (b^2-4 a c\right ) d^7 \sqrt {b d+2 c d x}+\frac {234}{5} c^2 d^5 (b d+2 c d x)^{5/2}-\frac {d (b d+2 c d x)^{13/2}}{2 \left (a+b x+c x^2\right )^2}-\frac {13 c d^3 (b d+2 c d x)^{9/2}}{2 \left (a+b x+c x^2\right )}-\left (117 c^2 \left (b^2-4 a c\right )^{3/2} d^8\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {b^2-4 a c} d-x^2} \, dx,x,\sqrt {d (b+2 c x)}\right )-\left (117 c^2 \left (b^2-4 a c\right )^{3/2} d^8\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {b^2-4 a c} d+x^2} \, dx,x,\sqrt {d (b+2 c x)}\right )\\ &=234 c^2 \left (b^2-4 a c\right ) d^7 \sqrt {b d+2 c d x}+\frac {234}{5} c^2 d^5 (b d+2 c d x)^{5/2}-\frac {d (b d+2 c d x)^{13/2}}{2 \left (a+b x+c x^2\right )^2}-\frac {13 c d^3 (b d+2 c d x)^{9/2}}{2 \left (a+b x+c x^2\right )}-117 c^2 \left (b^2-4 a c\right )^{5/4} d^{15/2} \tan ^{-1}\left (\frac {\sqrt {d (b+2 c x)}}{\sqrt [4]{b^2-4 a c} \sqrt {d}}\right )-117 c^2 \left (b^2-4 a c\right )^{5/4} d^{15/2} \tanh ^{-1}\left (\frac {\sqrt {d (b+2 c x)}}{\sqrt [4]{b^2-4 a c} \sqrt {d}}\right )\\ \end {align*}
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Mathematica [A] time = 0.77, size = 225, normalized size = 1.01 \begin {gather*} \frac {(d (b+2 c x))^{15/2} \left (91 \left (b^2-4 a c\right ) \left (-192 \left (b^2-4 a c\right ) (b+2 c x)^{5/2}+120 \left (b^2-4 a c\right )^2 \sqrt {b+2 c x}+60 c \sqrt [4]{b^2-4 a c} (a+x (b+c x)) \left (2 \left (b^2-4 a c\right )^{3/4} \sqrt {b+2 c x}-12 c (a+x (b+c x)) \left (\tan ^{-1}\left (\frac {\sqrt {b+2 c x}}{\sqrt [4]{b^2-4 a c}}\right )+\tanh ^{-1}\left (\frac {\sqrt {b+2 c x}}{\sqrt [4]{b^2-4 a c}}\right )\right )\right )+64 (b+2 c x)^{9/2}\right )+448 (b+2 c x)^{13/2}\right )}{560 (b+2 c x)^{15/2} (a+x (b+c x))^2} \end {gather*}
Antiderivative was successfully verified.
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IntegrateAlgebraic [C] time = 2.15, size = 465, normalized size = 2.09 \begin {gather*} \frac {\sqrt {b d+2 c d x} \left (-9360 a^3 c^3 d^7+2808 a^2 b^2 c^2 d^7-16848 a^2 b c^3 d^7 x-16848 a^2 c^4 d^7 x^2-65 a b^4 c d^7+5096 a b^3 c^2 d^7 x-1560 a b^2 c^3 d^7 x^2-13312 a b c^4 d^7 x^3-6656 a c^5 d^7 x^4-5 b^6 d^7-125 b^5 c d^7 x+1923 b^4 c^2 d^7 x^2+4608 b^3 c^3 d^7 x^3+3584 b^2 c^4 d^7 x^4+1536 b c^5 d^7 x^5+512 c^6 d^7 x^6\right )}{10 \left (a+b x+c x^2\right )^2}+\left (\frac {117}{2}-\frac {117 i}{2}\right ) \left (b^2 c^2 d^{15/2} \sqrt [4]{b^2-4 a c}-4 a c^3 d^{15/2} \sqrt [4]{b^2-4 a c}\right ) \tan ^{-1}\left (\frac {\sqrt {d} \left ((1-i) \sqrt {b^2-4 a c}+(-1-i) b-(2+2 i) c x\right )}{2 \sqrt [4]{b^2-4 a c} \sqrt {b d+2 c d x}}\right )-\left (\frac {117}{2}-\frac {117 i}{2}\right ) \left (b^2 c^2 d^{15/2} \sqrt [4]{b^2-4 a c}-4 a c^3 d^{15/2} \sqrt [4]{b^2-4 a c}\right ) \tanh ^{-1}\left (\frac {(1+i) \sqrt [4]{b^2-4 a c} \sqrt {b d+2 c d x}}{\sqrt {d} \left (\sqrt {b^2-4 a c}+i b+2 i c x\right )}\right ) \end {gather*}
Antiderivative was successfully verified.
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fricas [B] time = 0.46, size = 1077, normalized size = 4.85
result too large to display
Verification of antiderivative is not currently implemented for this CAS.
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giac [B] time = 0.39, size = 753, normalized size = 3.39 \begin {gather*} 192 \, \sqrt {2 \, c d x + b d} b^{2} c^{2} d^{7} - 768 \, \sqrt {2 \, c d x + b d} a c^{3} d^{7} + \frac {64}{5} \, {\left (2 \, c d x + b d\right )}^{\frac {5}{2}} c^{2} d^{5} - \frac {117}{2} \, {\left (\sqrt {2} {\left (-b^{2} d^{2} + 4 \, a c d^{2}\right )}^{\frac {1}{4}} b^{2} c^{2} d^{7} - 4 \, \sqrt {2} {\left (-b^{2} d^{2} + 4 \, a c d^{2}\right )}^{\frac {1}{4}} a c^{3} d^{7}\right )} \arctan \left (\frac {\sqrt {2} {\left (\sqrt {2} {\left (-b^{2} d^{2} + 4 \, a c d^{2}\right )}^{\frac {1}{4}} + 2 \, \sqrt {2 \, c d x + b d}\right )}}{2 \, {\left (-b^{2} d^{2} + 4 \, a c d^{2}\right )}^{\frac {1}{4}}}\right ) - \frac {117}{2} \, {\left (\sqrt {2} {\left (-b^{2} d^{2} + 4 \, a c d^{2}\right )}^{\frac {1}{4}} b^{2} c^{2} d^{7} - 4 \, \sqrt {2} {\left (-b^{2} d^{2} + 4 \, a c d^{2}\right )}^{\frac {1}{4}} a c^{3} d^{7}\right )} \arctan \left (-\frac {\sqrt {2} {\left (\sqrt {2} {\left (-b^{2} d^{2} + 4 \, a c d^{2}\right )}^{\frac {1}{4}} - 2 \, \sqrt {2 \, c d x + b d}\right )}}{2 \, {\left (-b^{2} d^{2} + 4 \, a c d^{2}\right )}^{\frac {1}{4}}}\right ) - \frac {117}{4} \, {\left (\sqrt {2} {\left (-b^{2} d^{2} + 4 \, a c d^{2}\right )}^{\frac {1}{4}} b^{2} c^{2} d^{7} - 4 \, \sqrt {2} {\left (-b^{2} d^{2} + 4 \, a c d^{2}\right )}^{\frac {1}{4}} a c^{3} d^{7}\right )} \log \left (2 \, c d x + b d + \sqrt {2} {\left (-b^{2} d^{2} + 4 \, a c d^{2}\right )}^{\frac {1}{4}} \sqrt {2 \, c d x + b d} + \sqrt {-b^{2} d^{2} + 4 \, a c d^{2}}\right ) + \frac {117}{4} \, {\left (\sqrt {2} {\left (-b^{2} d^{2} + 4 \, a c d^{2}\right )}^{\frac {1}{4}} b^{2} c^{2} d^{7} - 4 \, \sqrt {2} {\left (-b^{2} d^{2} + 4 \, a c d^{2}\right )}^{\frac {1}{4}} a c^{3} d^{7}\right )} \log \left (2 \, c d x + b d - \sqrt {2} {\left (-b^{2} d^{2} + 4 \, a c d^{2}\right )}^{\frac {1}{4}} \sqrt {2 \, c d x + b d} + \sqrt {-b^{2} d^{2} + 4 \, a c d^{2}}\right ) + \frac {2 \, {\left (21 \, \sqrt {2 \, c d x + b d} b^{6} c^{2} d^{11} - 252 \, \sqrt {2 \, c d x + b d} a b^{4} c^{3} d^{11} + 1008 \, \sqrt {2 \, c d x + b d} a^{2} b^{2} c^{4} d^{11} - 1344 \, \sqrt {2 \, c d x + b d} a^{3} c^{5} d^{11} - 25 \, {\left (2 \, c d x + b d\right )}^{\frac {5}{2}} b^{4} c^{2} d^{9} + 200 \, {\left (2 \, c d x + b d\right )}^{\frac {5}{2}} a b^{2} c^{3} d^{9} - 400 \, {\left (2 \, c d x + b d\right )}^{\frac {5}{2}} a^{2} c^{4} d^{9}\right )}}{{\left (b^{2} d^{2} - 4 \, a c d^{2} - {\left (2 \, c d x + b d\right )}^{2}\right )}^{2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.07, size = 1310, normalized size = 5.90
result too large to display
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: ValueError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 0.22, size = 966, normalized size = 4.35 \begin {gather*} \frac {64\,c^2\,d^5\,{\left (b\,d+2\,c\,d\,x\right )}^{5/2}}{5}-\frac {{\left (b\,d+2\,c\,d\,x\right )}^{5/2}\,\left (800\,a^2\,c^4\,d^9-400\,a\,b^2\,c^3\,d^9+50\,b^4\,c^2\,d^9\right )+\sqrt {b\,d+2\,c\,d\,x}\,\left (2688\,a^3\,c^5\,d^{11}-2016\,a^2\,b^2\,c^4\,d^{11}+504\,a\,b^4\,c^3\,d^{11}-42\,b^6\,c^2\,d^{11}\right )}{{\left (b\,d+2\,c\,d\,x\right )}^4-{\left (b\,d+2\,c\,d\,x\right )}^2\,\left (2\,b^2\,d^2-8\,a\,c\,d^2\right )+b^4\,d^4+16\,a^2\,c^2\,d^4-8\,a\,b^2\,c\,d^4}-192\,c^2\,d^7\,\sqrt {b\,d+2\,c\,d\,x}\,\left (4\,a\,c-b^2\right )-117\,c^2\,d^{15/2}\,\mathrm {atan}\left (\frac {b^2\,\sqrt {b\,d+2\,c\,d\,x}-4\,a\,c\,\sqrt {b\,d+2\,c\,d\,x}}{\sqrt {d}\,{\left (b^2-4\,a\,c\right )}^{5/4}}\right )\,{\left (b^2-4\,a\,c\right )}^{5/4}+c^2\,d^{15/2}\,\mathrm {atan}\left (\frac {\frac {c^2\,d^{15/2}\,\left (\sqrt {b\,d+2\,c\,d\,x}\,\left (56070144\,a^4\,c^8\,d^{18}-56070144\,a^3\,b^2\,c^7\,d^{18}+21026304\,a^2\,b^4\,c^6\,d^{18}-3504384\,a\,b^6\,c^5\,d^{18}+219024\,b^8\,c^4\,d^{18}\right )-\frac {117\,c^2\,d^{15/2}\,{\left (b^2-4\,a\,c\right )}^{5/4}\,\left (239616\,a^3\,c^5\,d^{11}-179712\,a^2\,b^2\,c^4\,d^{11}+44928\,a\,b^4\,c^3\,d^{11}-3744\,b^6\,c^2\,d^{11}\right )}{2}\right )\,{\left (b^2-4\,a\,c\right )}^{5/4}\,117{}\mathrm {i}}{2}+\frac {c^2\,d^{15/2}\,\left (\sqrt {b\,d+2\,c\,d\,x}\,\left (56070144\,a^4\,c^8\,d^{18}-56070144\,a^3\,b^2\,c^7\,d^{18}+21026304\,a^2\,b^4\,c^6\,d^{18}-3504384\,a\,b^6\,c^5\,d^{18}+219024\,b^8\,c^4\,d^{18}\right )+\frac {117\,c^2\,d^{15/2}\,{\left (b^2-4\,a\,c\right )}^{5/4}\,\left (239616\,a^3\,c^5\,d^{11}-179712\,a^2\,b^2\,c^4\,d^{11}+44928\,a\,b^4\,c^3\,d^{11}-3744\,b^6\,c^2\,d^{11}\right )}{2}\right )\,{\left (b^2-4\,a\,c\right )}^{5/4}\,117{}\mathrm {i}}{2}}{\frac {117\,c^2\,d^{15/2}\,\left (\sqrt {b\,d+2\,c\,d\,x}\,\left (56070144\,a^4\,c^8\,d^{18}-56070144\,a^3\,b^2\,c^7\,d^{18}+21026304\,a^2\,b^4\,c^6\,d^{18}-3504384\,a\,b^6\,c^5\,d^{18}+219024\,b^8\,c^4\,d^{18}\right )-\frac {117\,c^2\,d^{15/2}\,{\left (b^2-4\,a\,c\right )}^{5/4}\,\left (239616\,a^3\,c^5\,d^{11}-179712\,a^2\,b^2\,c^4\,d^{11}+44928\,a\,b^4\,c^3\,d^{11}-3744\,b^6\,c^2\,d^{11}\right )}{2}\right )\,{\left (b^2-4\,a\,c\right )}^{5/4}}{2}-\frac {117\,c^2\,d^{15/2}\,\left (\sqrt {b\,d+2\,c\,d\,x}\,\left (56070144\,a^4\,c^8\,d^{18}-56070144\,a^3\,b^2\,c^7\,d^{18}+21026304\,a^2\,b^4\,c^6\,d^{18}-3504384\,a\,b^6\,c^5\,d^{18}+219024\,b^8\,c^4\,d^{18}\right )+\frac {117\,c^2\,d^{15/2}\,{\left (b^2-4\,a\,c\right )}^{5/4}\,\left (239616\,a^3\,c^5\,d^{11}-179712\,a^2\,b^2\,c^4\,d^{11}+44928\,a\,b^4\,c^3\,d^{11}-3744\,b^6\,c^2\,d^{11}\right )}{2}\right )\,{\left (b^2-4\,a\,c\right )}^{5/4}}{2}}\right )\,{\left (b^2-4\,a\,c\right )}^{5/4}\,117{}\mathrm {i} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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